Why when traveling a curved path does acceleration go inwards?

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When traveling along a curved path, instantaneous acceleration points inward toward the concave side due to the change in direction of velocity, not its magnitude. While velocity is represented by the tangent line at a point on the curve, acceleration reflects the rate of change of this velocity vector. As an object turns, its direction changes, resulting in an inward acceleration that alters the velocity's direction. This inward acceleration is essential for maintaining circular motion, contrasting with the constant velocity along a straight path. Understanding this concept is crucial for grasping the dynamics of motion in physics.
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Hello, I am having some trouble wrapping my mind around this concept. In the beginning of calculus I was taught that the derivative is relationship of change of one variable with respect to another variable, and that a good way to visualize this is the tangent of a curve at a point. My physics textbook notes that when traveling a curved path the instantaneous acceleration is pointed towards the concave side of the path. I do not quite understand why?

To find instantaneous velocity, even around a curved path it is the tangent line of the curve at a point. Why is acceleration different?
 
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Because acceleration is the change in velocity. How does the velocity change when you make a turn?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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