Will the Cart Roll Down the Hill Despite Friction?

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SUMMARY

The discussion centers on the physics problem of a 0.80-kg cart rolling down a 30.0° hill with a vertical height of 0.50 m and a frictional force of 5.0 N acting against it. The gravitational force acting on the cart is calculated to be 7.84 N, with the downhill component being 3.92 N. Since the frictional force exceeds the downhill component of gravity, the cart does not roll to the bottom of the hill and will instead accelerate uphill.

PREREQUISITES
  • Understanding of Newton's second law (f=ma)
  • Basic knowledge of gravitational force calculations
  • Friction force concepts in physics
  • Trigonometric functions related to angles (sine function)
NEXT STEPS
  • Study the effects of friction on motion in physics
  • Learn about gravitational force components on inclined planes
  • Explore advanced problems involving friction and acceleration
  • Investigate the role of mass and angle in determining motion outcomes
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Students studying physics, educators teaching mechanics, and anyone interested in understanding forces acting on objects on inclined planes.

rawr8712
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Homework Statement


An 0.80-kg cart rolls down a 30.0° hill from a
vertical height of 0.50 m. The distance that the cart must roll to the bottom of
the hill is 0.50 m/sin 30.0°=1.0 m. The surface of
the hill exerts a frictional force of 5.0 N on the cart.
Does the cart roll to the bottom of the hill?

Homework Equations


I do know what equation to use or how to get the problem started.
f=ma

The Attempt at a Solution


F=9.8m/s^2(.8kg)
F=7.84N(sin30)
F=3.92N
so it doesn't over come the frictional force.
 
Last edited:
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rawr8712 said:

Homework Statement


An 0.80-kg cart rolls down a 30.0° hill from a
vertical height of 0.50 m. The distance that the cart must roll to the bottom of
the hill is 0.50 m/sin 30.0°=1.0 m. The surface of
the hill exerts a frictional force of 5.0 N on the cart.
Does the cart roll to the bottom of the hill?

Hi rawr8712! Welcome to PF! :smile:

Yes, the downhill component of gravity is 3.92N, so if the friction force is 5N, the cart will accelerate uphill!. :rolleyes:

Are you sure you've copied the question accurately?​
 


tiny-tim said:
Hi rawr8712! Welcome to PF! :smile:

Yes, the downhill component of gravity is 3.92N, so if the friction force is 5N, the cart will accelerate uphill!. :rolleyes:

Are you sure you've copied the question accurately?​

the cart will not accelerate up the hill seeing as the force stated for friction is the maximum force that friction can exert not a constant. therefore the cart will not move
 

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