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Forums
Engineering
Electrical Engineering
Will the maximum discharge current double for two parallel batteries?
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[QUOTE="gleem, post: 5999815, member: 298988"] If I interpret this correctly the resistance of the wire is independent of the voltage across it. However using 12V for a given wire length will produce more current according to Ohm's law. A particular type and gauge wire as a copper 14 AWG is rated to carry a maximum current depending on a particular maximum wire temperature , the insulation and ambient temperature, called its ampacity.. For #14 it is 20 amps for 90 deg C in an ambient temp of 30 deg C. See [URL]http://www.usawire-cable.com/pdfs/nec%20ampacities.pdf[/URL] for a chart for various gauges. A consideration of what gauge wire you choose and its length to and from the the source will depend on how much voltage drop on the wire you can tolerate. Another way to think about it is how much less voltage than the 3.7 V your device is spec'd for will be acceptable. Will it run properly at 3.4V for example? Take #14 wire at 18 A. The wire has a resistance of .00252 ohms/ft. which seems small. If you use 10 ft of wire (5 to the device and 5 back to the battery) the voltage available to your device will be 3.7V (battery voltage) - 10ft×.00252ohms/ft×18A (voltage drop across the wire) = 3.25V(voltage available for your device) Will you device run properly at this voltage? If not then you need to shorten the wire or use a lower gauge. [/QUOTE]
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Engineering
Electrical Engineering
Will the maximum discharge current double for two parallel batteries?
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