Wind velocity and aircraft (answer check)

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Homework Help Overview

The problem involves calculating wind velocity in the context of an aircraft's flight path. The scenario includes a specified flight distance, aircraft speed, and a required heading adjustment due to wind influence.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of effective southward velocity and the components of actual velocity. There is an emphasis on ensuring the final wind velocity is determined correctly, with some participants suggesting the need for numerical verification.

Discussion Status

Some participants have provided numerical results and confirmed answers, while others are focused on the calculation process and ensuring accuracy. There is an ongoing exploration of the problem without a definitive consensus on the method used.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of discussion regarding methods or assumptions. The problem setup includes specific directional components and speed values that are under scrutiny.

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Homework Statement



You’re a pilot beginning a 1500-km flight. Your plane’s speed is 1000 km/h, and air traffic control says you’ll have to head 15° west of south to maintain a southward course. If the flight takes 100 min, what’s the wind velocity?

The Attempt at a Solution



veffective south = vactual + vwind

veffective south = 1500kmh^-1 / 1.667hr = ( 0, -900kmh^-1 )

vactual = (1000kmh^-1 cos 255, 1000kmh^-1 sin 255) = (-258.82kmh^-1 , -965.93kmh^-1)

vwind = veffective south - vactual

therefore

(0, -900kmh^-1 ) - (-258,82kmh^-1, -965.93kmh^-1)
= (258.82kmh^-1 , 65.93kmh^-1)
= |vwind| = SQRT [ (258.82kmh^-1)^2 + (65.93kmh^-1) ^2]
 
Last edited:
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I think you should punch the final numbers in your calculator, take the square root, and come up with one number for the answer.
 
SteamKing said:
I think you should punch the final numbers in your calculator, take the square root, and come up with one number for the answer.

The answer is 267kmh^-1
 
I confirm that answer.
 

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