(adsbygoogle = window.adsbygoogle || []).push({}); Sally applies a horizontal force of 520 N with a rope to drag wooden crate across a floor with a constant speed. The rope tied to the crate is pulled at an angle of 53.0°.

(a) How much force is exerted by the rope on the crate?

Solved and correct.

(b) What work is done by Sally if the crate is moved 28.5 m?

Solved and correct

(c) What work is done by the floor through force of friction between the floor and the crate?

This one I have no idea how to do, unfortunately :(

FxD=Work

Trig (cos, sine, tan)

Work=F(d)+(friction force)(d)

work= change in Kinetic Energy

Potential Energy=mass(g)(Height)

(a) How much force is exerted by the rope on the crate?

I managed to figure this one out.

cos53=520N/x

cos53x=520

x=864.05 N

(b) What work is done by Sally if the crate is moved 28.5 m?

All I did with this one was multiply force (520) by distance (28.5) and got 14820 J

(c) What work is done by the floor through force of friction between the floor and the crate?

This one I have no idea how to do, unfortunately :(

I've unfortunately procrastinated and it's due tomorrow but I'm sure I'll manage if someone doesn't reply....:/

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# Homework Help: Work and energy and that sort of rot. :/

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