Work and Energy: Find the Angle of Force - 65 Characters

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SUMMARY

The discussion revolves around calculating the angle of force in a physics problem involving work, force, and displacement. Given a force of 5 Newtons acting over a distance of 10 meters resulting in 25 joules of work, the angle θ is determined using the formula W = F·d·cos(θ). The calculation leads to cos(θ) = 0.5, which corresponds to an angle of 60 degrees. Participants confirm the solution and emphasize the importance of memorizing trigonometric values for efficiency in problem-solving.

PREREQUISITES
  • Understanding of basic physics concepts such as work and force
  • Familiarity with the formula W = F·d·cos(θ)
  • Basic knowledge of trigonometry, specifically cosine values
  • Ability to perform inverse trigonometric calculations
NEXT STEPS
  • Study the derivation and applications of the work-energy theorem
  • Learn about trigonometric identities and their applications in physics
  • Explore the concept of vector components in force analysis
  • Practice solving physics problems involving work and angles using different forces
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone looking to enhance their understanding of work and energy concepts in relation to force angles.

alijan kk
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Homework Statement


A body moves a distance of 10 meter along a straight line under the action of a force of 5 Newtons. If work done is 25 joules, the angle which the force takes with the direction of motion of the body is:
a: 0 degree
b: 30 degree
c: 60 degree
d: 90 degree

Homework Equations


work=fdcostheta

The Attempt at a Solution


what formula should we use to get the degree or how to figure out it by making a picture?
 
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Based on the work's definition, to be honest, the more precise version of what you wrote in the Relevant equations, you have to find ##F\cdot d,## since the force is a constant vector here. Hence by what you had, you can get ##W=F\cdot d=|F||d|\cos\theta,## which can lead you to what you want.
 
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tommyxu3 said:
Based on the work's definition, to be honest, the more precise version of what you wrote in the Relevant equations, you have to find ##F\cdot d,## since the force is a constant vector here. Hence by what you had, you can get ##W=F\cdot d=|F||d|\cos\theta,## which can lead you to what you want.

work = FDcos
25=5*10*cose
25=50*cos
cos=25/50
cos=0.5

but what now? 1/2 or 0.5 is equalt to what?? help
 
work = FDcos
25=5*10*cose
25=50*cos
cos=25/50
cos=0.5

but what now? 1/2 or 0.5 is equalt to what?? help
 
The value ##0.5## you get is the cosine of the angle ##\theta,## which the the angle of the force and the displacement. Do you realize these?
 
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Inverse cos (0.5)=60
 
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tommyxu3 said:
The value ##0.5## you get is the cosine of the angle ##\theta,## which the the angle of the force and the displacement. Do you realize these?

yes but on calculator the value of cosetheta is 0.99?
can you get the answer of the given options above?
 
Now the question is given ##\cos\theta=0.5## and you have to find the ##\theta## between ##0## to ##180## degrees. Right?
 
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Parsifal1 said:
Inverse cos (0.5)=60[/QUOTEo
OH! yes the inverse of 0.5 is 60 !
but why we are using inverse cosine?
 
  • #10
tommyxu3 said:
Now the question is given ##\cos\theta=0.5## and you have to find the ##\theta## between ##0## to ##180## degrees. Right?
yes it is 60 by using inverse cosine theta !
 
  • #11
That's how you find x in cos(x)
 
  • #12
You don't have to apply the idea of inverse function, though the same, but just have to know what you want, with some basic knowledge of trigonometry, like ##\cos 60^{\circ}=\frac{1}{2}.##
 
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  • #13
25=(5*10)cos(x)
25/(5*10)=cos(x)=0.5
cos^-1 (0.5)=60
 
  • #14
Parsifal1 said:
That's how you find x in cos(x)
oh! thank you for your quick help. appreciat
 
  • #15
tommyxu3 said:
You don't have to apply the idea of inverse function, though the same, but just have to know what you want, with some basic knowledge of trigonometry, like ##\cos 60^{\circ}=\frac{1}{2}.##
yes you are right if have this value memorized i would have done thi question in seconds thankyou i will memorize cos30 cos60 and cos90 values right?
 
  • #16
Parsifal1 said:
25=(5*10)cos(x)
25/(5*10)=cos(x)=0.5
cos^-1 (0.5)=60
thanks
 
  • #17
If you keep learning other physics knowledge, then you'll keep being with these basic concepts, and finally you will memorize, or say acquire, them naturally.
 
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  • #18
alijan kk said:

Homework Statement


A body moves a distance of 10 meter along a straight line under the action of a force of 5 Newtons. If work done is 25 joules, the angle which the force takes with the direction of motion of the body is:
a: 0 degree
b: 30 degree
c: 60 degree
d: 90 degree

Homework Equations


work=fdcostheta

The Attempt at a Solution


what formula should we use to get the degree or how to figure out it by making a picture?
60°
 
  • #19
A@bhishek said:
60°
yes you are right , this question is solved
 

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