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gbaby370

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I had a question which asked, "A 12 kg wagon is being pulled at an angle of 38° above horizontal. What force is applied to the wagon if it accelerates from rest to a speed of 2.2 m/s over a distance of 3.4 m?"

For the record this is just a practice question and I am simply posting for feedback if I have made an error somewhere.

Given we have m= 12kg F=? Angle= 38 degrees V1=0 V2=2.2 Δd=3.4

I used the equation;

Work = Change in energy

W=ΔE

FcosθΔd=(0.5)mv2^2-(0.5)mv1^2

I rearranged and got.

F=(0.5)mv2^2/cosθΔd

F=(0.5)(12)(2.2^2)/cos38(3.4)

F=10.8N

How's that look?

The question might seem simple but I've been out of high school for several year and am hoping to go back to school, so I am just trying to ensure I'm remembering all of the fundamentals.