Work and Energy with Electricity

[xxkbxx]

Homework Statement

A 0.010-kg positively-charged particle is accelerated by a uniform electric field directed to the right. The object accelerates from 5.0 to 15.0 m/s while traveling a distance of 0.10 m.

Use the definition of potential energy to determine the change in electric potential energy of the particle. Is the change an increase or a decrease?

Homework Equations

Wel = Kf - Ki
Wel = -Delta-U
Delta-V = W/q0

The Attempt at a Solution

The definition of electric potential is equal to -delta-U / q0
Delta-U is negative because the work of the problem from Electric Field comes out to 1 Joule from the definition of work. So, delta-U is -1 J, meaning that the electric potential change is positive since q0 is positive - but I cannot figure out how to find q0's magnitude. I'm pretty sure I'm missing something from the given to determine the value of q0, but I'm otherwise stumped!

 

[turdferguson]

you know the change in KE, use that to find the change in U and q

 

[xxkbxx]

How do they compare? I cannot find an equation in my textbook related U and q to the Change in Kinetic Energy.

 

[turdferguson]

Law of Conservation of Energy, what its lost in potential it has gained in kinetic. U=qdeltaV

 

[xxkbxx]

Still though, I know U, but I don't know my q or delta-V values. Let me know if I'm overlooking something obvious that you're assuming that I know!

 

[turdferguson]

You know the field and the distance it acts over

 

[xxkbxx]

Gotcha, it looks a lot better after a nights rest, I kept thinking it was Electric Potential, not Electric Potential Energy