Work and Fluid Force, lifting water out of a triangular prism tank

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Homework Help Overview

The problem involves calculating the work done in emptying a triangular prism tank filled with water. The tank has specific dimensions and requires the water to be pumped to a certain height. The context includes considerations of fluid force and the geometry of the tank.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss finding the width of the tank as a function of height, with references to similar triangles and linear relationships. There are attempts to relate the geometry of the tank to the calculation of work through integration. Some participants suggest using conservation of energy concepts, while others express uncertainty about the required approach.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. Some guidance has been offered regarding finding the width as a function of height, but there is no explicit consensus on the best method to proceed. Participants are actively questioning assumptions and seeking clarification on specific steps.

Contextual Notes

There is mention of constraints related to the course focus on calculus rather than physics, which influences the approaches discussed. Participants are also grappling with the clarity of the problem statement and the definitions involved in the calculations.

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Homework Statement


A vertical cross section of a tank is shown. Assume the tank is 16 feet long and full of water. (\delta=62.4, and that the water is to be pumped to a height of 8 feet above the top of the tank. Find the work done in emptying the tank. The tank is a triangular prisim with base=5ft and height=8ft.

Homework Equations


Not sure that there are any.

The Attempt at a Solution


First, I am supposed to find the force of the water. It says to find the width as a function of the height, and the book is unclear how to do this very well. From what I can gather it's the height divided by half the base equals the distance to pump the water divided by W, W being the width. So I solved and got W=\frac{5}{2}-\frac{5}{16}y. And then since work is force times height, you just multiply that by the distance it has to be lifted, that's 16-y. And that's your integrad, but you have a 16\delta factor too, but you just bring that outside of your integral. After I simply the integrand and anti differentiate I got 40y-\frac{15}{4}y^{2}+\frac{5}{48}y^{3} evaluated from 0 to 8, again, with the factor of 16\delta. Fundamental theorem it and I got 132787 rounded to the nearest whole number. The answer is wrong, and I'm fairly certain I know how to do all of this except finding the width as a function of the height. The book says it has to do with similar triangles. But I don't get what they are saying. Can someone shed some light on this for me?
 
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how about using conservation of energy and consider the centre of mass's
 
Because this is a calculus 2 class, not a physics class, I don't know how to do it that way. I know how to find the centroid of an area that has uniform density, but that's not how we are supposed to do it.
 
ok well i would find w(h)

then infinetsimal vol element
dV = w(h).L.dh

think of the work dW required to get this infinitesimal element to the reuired hieght and then integrate over h

its all the same thing though
 
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That's what I'm having trouble with. I can't find the infitesimal volume, I can't get the width as a function of the height. Could you walk me through it?
 
changed notation in last post

ok so you know
w(0) = 5
w(8) = 0

and as its a triangle, its width will vary linearly in between...

so basically you have two points (0,5) and (8,0) find the equation of the line that connects them, and that will be w(h)
 

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