A force Fx acts on a particle that has a mass of 1.5kg. The force is related to the position x of the particle by the formula Fx = Cx^3, where C = .50 if x is in meters and Fx is in newtons. a) What are the SI units of C? b)Find the work done by this force as the particle moves from x=3.0m to x=1.5m c)At x = 3.0m, the force points opposite the direction of particle's velocity(speed is 12.0m/s). What is its speed at x=1.5m? For A: Isn't C just a constant? What units is this in? For B: I have to integrate Fx and the integral of F(x)dx = x^4/4 Since C is a constant I can put it in front of the integral so is 1/4 C x^4 When I integrate shouldn't there be a + K? 1/4 C x^4 + K X1 = 3.0 and X2 = 1.5 Plug in and solve? For C: Using answer from Part B = Work total Work total = 1/2 M Vf^2 - 1/2 M Vi^2 where Vi = 12m/s?