Work and Power of 1.83x10^3 kg Car Accelerating from Rest

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SUMMARY

The discussion focuses on calculating the work done and power delivered by a 1.83x103 kg car accelerating uniformly from rest to 13.6 m/s in 2.81 seconds. The correct approach involves determining the acceleration as 4.84 m/s2 rather than using gravitational force. The work done on the car can be calculated using the formula w = f * d, where force (f) is derived from mass and acceleration, and distance (d) is determined using the kinematic equation. Power is then calculated using p = w/t.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with kinematic equations
  • Knowledge of work-energy principles
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate work done using the formula w = f * d with the correct force derived from acceleration.
  • Learn how to derive distance using the kinematic equation d = v0t + 0.5at2.
  • Explore the relationship between work and power in mechanical systems.
  • Study examples of uniform acceleration problems to reinforce understanding.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of work and power calculations in uniform acceleration scenarios.

PepeF.
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Homework Statement


a 1.83x10^3 kg car accelerates uniformly from rest to 13.6m/s in 2.81 s

-what is the work done on the car in this time inerval?

-what is the power delivered by the engine in thsi time interval?



Homework Equations



w=f*d
p=w/t

The Attempt at a Solution



i did the first one, but could not be able to come up with the answer
i multiplied gravity x mass = f then fxd=246568 and its wrong
can you please explain or tell me how to get it
 
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PepeF. said:

Homework Statement


a 1.83x10^3 kg car accelerates uniformly from rest to 13.6m/s in 2.81 s

-what is the work done on the car in this time inerval?

-what is the power delivered by the engine in thsi time interval?



Homework Equations



w=f*d
p=w/t

The Attempt at a Solution



i did the first one, but could not be able to come up with the answer
i multiplied gravity x mass = f then fxd=246568 and its wrong
can you please explain or tell me how to get it

Because your acceleration is not gravity, it is the acceleration that is implied in the problem:

[tex] a=\frac{v_f-v_0}{t}=\frac{13.6m/s-0m/s}{2.81s}=4.84m/s^2[/tex]
 

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