Work and Voltage Change in Moving a Proton from Infinity to 0.16m

[ParoXsitiC]

Homework Statement

Known:

Potential Difference of range 0.16 m < r < infinity is -562 kilovolts
At r = 0.16 there is a -10 μC charge on a conducting sphereQuestion:

How much work would the field do if a proton were moved from infinity to 0.16m? comment on the meaning of the sign.

Homework Equations

W = -ΔU = -q * ΔV
1 e = 1.60 x 10 ^-19 C
1 proton = +1e

The Attempt at a Solution

q = 1.60 x 10 ^-19 C
ΔV = -562 kV
W = -q * ΔV
... = -1.60 x 10 ^-19 C * -562 kV
... = 89.9 x 10 ^-15 J

However, shouldn't a proton wan't to approach a negative charge and thus the work should be negative?

 

[vela]

The proton is brought in from infinitely far away to r=0.16 m. It moves toward the negative charge, and the force on it due to the field also points toward the negative charge, so the work should be positive, no?