Work Done by Father on Girl's Sled Up Hill

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SUMMARY

The problem involves calculating the work done by a father pushing his daughter's sled up a snowy incline with a height of 3.6 meters and an angle of 15 degrees. Given the mass of the girl and sled is 35 kg and the coefficient of kinetic friction is 0.20, the work done can be calculated using the formula W = mgh, resulting in a total work of 2300 J. The solution requires determining the force parallel to the motion and the distance traveled along the incline.

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  • Understanding of Newton's laws of motion
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  • Knowledge of trigonometric functions for incline calculations
  • Basic understanding of friction and its effects on motion
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Homework Statement



A father pushes horizontally on his daughter’s sled to move it up a snowy incline. If the sled moves up the hill with a constant velocity, how much work is done by the father in moving it from the bottom to the top of the hill? The angle is 15 degrees, the top of hill is 3.6 meters high, the mass of girl and sled is 35 kg, and the coefficient of kinetic friction is 0.20.

Homework Equations





The Attempt at a Solution



I know that you have to sum the x and y components, and I know the y component is W=mgh=(35kg)(9.8 m/s^2)(3.6 m), and I know the final answer is 2300 J but I don't know how to get there.
 
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Work relates to the force parallel to the motion. Find that force first (i.e. turn the problem into a 1-d problem). Then find the distance of the motion. in this problem, it's easier that way... the motion is in a straight line against a constant force (caused by gravity in part and friction in part).
 

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