1. The problem statement, all variables and given/known data A father pushes horizontally on his daughter's sled to move it up a snowy incline, as illustrated in the figure, with h = 4.4 m and θ = 10°. The total mass of the sled and the girl is 35 kg and the coefficient of kinetic friction between the sled runners and the snow is 0.20. If the sled moves up the hill with a constant velocity, how much work is done by the father in moving it from the bottom to the top of the hill? 2. Relevant equations W = Fp * d 3. The attempt at a solution 2 things have to be overcome, gravity and the friction. 1. For gravity: F = m*g*h = (35kg)(9.8m/s^2)(4.4m) = 1509 N 2. Friction: W = fk * d. fk = uk*m*g*cos(10) = (.2)(35kg)(9.8m/s^2)*cos(10) = 67.56 d = h/sin(theta) = 4.4/sin(10) = 25.34 w = 67.56 * 25.34 = 1712 N So the total force exerted by the father should be 1509N + 1712N = 3221 N but this is wrong. What am I missing?