Work done by the system, positive or negative?

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SUMMARY

The discussion clarifies the conventions surrounding the sign of work done by a system in thermodynamics, highlighting that both positive and negative designations are valid depending on the context. In the equation for the first law of thermodynamics, if expressed as ΔU=Q-W, work (W) is defined as the work done by the system on the surroundings, resulting in a negative value. Conversely, if the equation is written as ΔU=Q+W, W represents the work done by the surroundings on the system, leading to a positive value. Consistency in the chosen convention is essential for accurate calculations.

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My chemistry course says that work done by the system is negative, but physics course says that work done by the system is positive, I'm sure I'm missing something and I really need to understand it. Thanks.
 
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It is a question of convention. Both approaches are valid, so long as one uses the right sign in from of W.

For a particular calculation, once you've decided on a convention, just be careful to be consistent.
 
To add to what @DrClaude said, if the first law is written as ##\Delta U=Q-W##, then W is the work done by the system on the surroundings. If it is written as ##\Delta U=Q+W##, then W is the work done by the surroundings on the system.
 
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