Work done climbing a flight of stairs.

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Homework Help Overview

The discussion revolves around calculating the work done by a firefighter climbing a flight of stairs, focusing on the concepts of force, gravitational potential energy, and significant figures in the context of physics problems.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate work without being given a force or acceleration. Some participants introduce the concept of gravitational potential energy and discuss the weight of the firefighter as a force. There is also a discussion about significant figures in the final answer.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of the information provided. Guidance has been offered regarding the calculation of force and the relationship between work and gravitational potential energy, along with considerations for significant figures.

Contextual Notes

There is an emphasis on the assumptions related to the firefighter's weight on Earth and the significance of using correct significant figures in the calculations.

fattydq
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A 58 kg firefighter climbs a flight of stairs 5.3 m high. How much work is required?

I know work is just force times distance, but I'm not given a force? And I can't really find a force because force is mass times acceleration and I'm not given an acceleration...help!
 
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Do you know about gravitational potential energy?

Actually you are given a force, if he has a mass of 58kg (you must have some skinny firemen!) and he is on Earth, how much does he weigh?
 
mgb_phys said:
Do you know about gravitational potential energy?

Actually you are given a force, if he has a mass of 58kg (you must have some skinny firemen!) and he is on Earth, how much does he weigh?

9.8 times 58...so 568.4 N right? Then 568.4 times 5.3m and you get 3012.52, yes? Would the unit be joules?
 
Yes - but think about how many significant figures you should have

The equation for potential energy = m g h
As you said this is the same as force (mg) * distance (h)
And yes J = N m = kg m^2/s^2
 
Would it just be 3.0 times 10^3 in correct sig figs?
 
Last edited:
?
 
Yes, you have 2 sig figures for the mass and height so it's two sig figures for the answer.
So formally 3.0 x 10^3 J or 3000J would probably be ok.
 

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