Finding work of a man running up stairs

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Homework Help Overview

The problem involves calculating the work done and power generated by a person, Jerome, as he runs up a staircase, elevating his body over a specified vertical distance and time. The context is rooted in physics, specifically in the concepts of work and power.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the work equation W=Fdcosθ, questioning the role of the angle θ and the correct force to use in the calculations. There is also confusion regarding the displacement and whether the vertical height can be used directly in the work calculation.

Discussion Status

The discussion is ongoing, with participants exploring the definitions and implications of work and displacement. Some guidance has been offered regarding the relationship between force, displacement, and the angle involved, but no consensus has been reached on the correct approach to the problem.

Contextual Notes

Participants note the absence of specific information about the slope of the stairs and the direction of forces involved, which adds to the complexity of the problem. There is a concern about adhering to the lesson's focus on work without resorting to energy methods.

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Homework Statement


During the Powerhouse lab, Jerome runs up the stairs, elevating his 102 kg body a vertical distance of 2.29 meters in a time of 1.32 seconds at a constant speed.

a. Determine the work done by Jerome in climbing the stair case.
b. Determine the power generated by Jerome.
(credit : http://www.physicsclassroom.com/ )

Homework Equations


W=Fdcosθ
P=W/t[/B]

The Attempt at a Solution


well, I got the right answers but I don't get it why I can directly use 102 kg for F=ma in W=Fdcosθ equation to find work and the problem doesn't give me any theta or I miss some concept of work?
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Pao44445 said:
W=Fdcosθ
In that equation, what does theta represent in terms of the vectors ##\vec F## and ##\vec d##?
 
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The equation is ##W=\vec s \cdot \vec F## for the work done applying force F.
Notice that Jerome runs at constant velocity? Therefore the net force on him is zero.
Therefore your force diagram is incorrect.
 
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haruspex said:
In that equation, what does theta represent in terms of the vectors ##\vec F## and ##\vec d##?
An angle between Force and distance?
 
Pao44445 said:
An angle between Force and distance?
With post #3 in mind, what is the magnitude and direction of the force?
What is the magnitude and direction of the distance?
 
jbriggs444 said:
With post #3 in mind, what is the magnitude and direction of the force?
What is the magnitude and direction of the distance?
I came back reading definition of work again
"Work results when a force acts upon an object to cause a displacement"
F that I must use in this equation is the force that the stairs act on him? (N) and distance has no direction since it is scalar quantity. I am confusing :/ Why I can use 2.29 m for d which it is the height of stair not the displacement of the man(Hypotenuse). I can use energy to solve this but this lesson is about work and I don't want to cheat too
 
Pao44445 said:
F that I must use in this equation is the force that the stairs act on him?
Yes, and in what direction is that?
Pao44445 said:
distance has no direction since it is scalar quantity
Right, but the definition you quote says displacement, which is a vector.
It is fine to use the displacement along the slope of the stairway,provided you use the right vector for the force and take into account the angle between the two.
Now, you may object that you are not told the slope nor the distance up it of the displacement, but if you just create variables for those and apply a bit of trigonometry you should find they disappear from the equation.
 

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