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A force F = (6x i + 5y j) N acts on an object as it moves in the x direction from the origin to x = 5.04 m. Find the work (work = integral of F (dot product) dx done on the object by the force.

I am confused as to what dx would be in this equation, and how to find it.

The work that I've done so far is (using an equation from my book) W= F(dot product) change in x. First off, will this equation even work? Its a little different than the first one I wrote. But second, since the dot product is used for two vectors i wrote the change in x part of that equation as a vector <5.04, 0>. So taking <5.04, 0> (dot product) <6x, 5y> = 30.42x. I don't think there should be a variable in my answer so I tried to answer with 30.42 but that isn't correct.

I have a feeling that I am far off base with what I've done so far. Please help, thank you.

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# Homework Help: Work done on a force using dot product

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