Work Done on Jet by Engines & Catapult during Launch

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SUMMARY

The discussion focuses on calculating the work done on a 17,000 kg jet during its launch from an aircraft carrier using a catapult. The jet's engines exert a constant thrust force of 160 kN. The correct approach to calculate work involves using the formula W = Fd, where the angle θ is not necessary when force and displacement are in the same direction. The initial calculation incorrectly included a cosine factor, leading to a negative work result, which was clarified as an error in understanding the direction of force and displacement.

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Homework Statement


A 17000kg jet takes off from an aircraft carrier via a catapult. The gases thrust out from the jet's engines exert a constant force of 160 kN on the jet;the force exerted on the jet by the catapult is plotted in the figure b.

a)Determine the work done on the jet by the gases expelled by its engines during launch of the jet.
b)Determine the work done on the jet by the catapult during launch of the jet.

GIANCOLI.ch07.p13.jpg


Homework Equations


W=Fdcos\theta

The Attempt at a Solution



a)Since no displacement is stated outright, I assumed that it is 85m from the plot.
160kN=160,000N
W=160000*85*cos(180)=-1.36*10^7

This was an incorrect answer. What did I do wrong?
 
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Symstar said:

Homework Statement


A 17000kg jet takes off from an aircraft carrier via a catapult. The gases thrust out from the jet's engines exert a constant force of 160 kN on the jet;the force exerted on the jet by the catapult is plotted in the figure b.

a)Determine the work done on the jet by the gases expelled by its engines during launch of the jet.
b)Determine the work done on the jet by the catapult during launch of the jet.

Homework Equations


W=Fdcos\theta

The Attempt at a Solution



a)Since no displacement is stated outright, I assumed that it is 85m from the plot.
160kN=160,000N
W=160000*85*cos(180)=-1.36*10^7

This was an incorrect answer. What did I do wrong?

Since it is the Force over positive distance and the Force is in the direction of Positive distance, then the work is positive. You don't need Cosθ. The positive force goes to build positive KE which is increasing V2 not decreasing.
 
Thanks, I was a little thrown off by the thrust out of the back of the plane I guess.
 

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