Work Done on Trunk by Applied Force P: 8.83 J

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SUMMARY

The work done on a trunk of mass 2.3 kg pushed up an incline at an angle of 18.0° by a horizontal force of 225 N is calculated to be 8.83 J. The coefficient of kinetic friction between the trunk and the incline is 0.22, leading to a frictional force of 4.72 N. The correct calculation for the work done by friction should account for the perpendicular component of the applied force P, which affects the normal force and thus the frictional force. The final work done by friction is -8.83 J due to its opposing direction to the movement.

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Homework Statement


A trunk of mass m = 2.3 kg is pushed a distance d = 187 cm up an incline with an angle of inclination q = 18.0° by a constant horizontal force P = 225 N (see figure). The coefficient of kinetic friction between the trunk and the incline is 0.22. Calculate the work done on the trunk by the applied force P.

Calculate the work done on the trunk by the frictional force.

[PLAIN]http://img706.imageshack.us/img706/9623/prob13a.gif


Homework Equations


work=F*D
Fk=Fn*Uf

The Attempt at a Solution



I solved for the work of the push, for the work of friction I am doing this

.22*2.3*9.81*cos(18)=4.72N
4.72N*1.87m=8.83 J, and because the work is on the negative direction of the movement its -8.83.

Keeps saying my answer is wrong.
 
Last edited by a moderator:
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A simple mistake. You're doing it all correctly, and you're going to hate this. You simply forgot to consider the component of P that is perpendicular to the ramp when calculating the frictional force. =/
 

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