- #1
gunster
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Homework Statement
A spring has a relaxed length of 5 cm and a
stiffness of 95 N/m. How much work must you
do to change its length from 2 cm to 10 cm?
k=95
Lnull=0.05
delta x = .1-.02 = 0.08
Homework Equations
F=-kx
W=Fdcostheta
The Attempt at a Solution
I honestly have tried everything and am beginning to think I am way off the mark and missed something. But what i tried was
W = Fdcostheta where F = -kx
Therefore, since force changes direction after the displacement is past the relaxed spring length, i used:
W = -95 * (0.05-0.02) * (0.05-0.02) cos 0 + -95 * (0.1-0.5) * (0.1-0.5) cos 180
But that was apparently completely wrong. any help please?