Work done to reach the point where the gravitational potential is zero

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SUMMARY

The discussion focuses on calculating gravitational potential, specifically the work done to move an object from infinity to a specific location, and vice versa. The user correctly identifies that gravitational potential is defined as the work done per kilogram to bring an object from infinity to its current position. They also note that the work required to return the object to infinity is equal in magnitude but opposite in sign. The user assumes a 5 kg mass is located at the Earth's surface, using the Earth's radius for calculations.

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Bolter
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Homework Statement
Calculate the work done on the mass to a point where the gravitational potential is zero
Relevant Equations
V = –GM/r
Hi there

I have been attempting the parts to this question and I'm finding some trouble on how to answer the last part which is d)iii

IMG_3719.JPG


Here is what I have done for the rest of the parts and what I think I should start off with in part d)iii

IMG_3716.JPG

IMG_3717.JPG

IMG_3718.JPG


Thanks!
 
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Gravitational potential represents the work done (per kg) in order to bring the object from infinity to its current location.

1579894946508.png


By symmetry, the work to send the object back to infinity must be the same but of opposite sign.
 
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gneill said:
Gravitational potential represents the work done (per kg) in order to bring the object from infinity to its current location.

View attachment 256044

By symmetry, the work to send the object back to infinity must be the same but of opposite sign.

I see, this is what I have tried now

IMG_3720.JPG


Where I assumed that the current location of the 5 kg mass was lying at the surface of the Earth so the distance r was the radius of the Earth then
 
Given your assumption that looks good.
 

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