Work done to reach the point where the gravitational potential is zero

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Homework Help Overview

The discussion revolves around a problem related to gravitational potential and the work done to move an object in a gravitational field, specifically addressing a scenario where the gravitational potential is zero.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify their understanding of the work done in relation to gravitational potential, particularly in the context of moving an object from a specific location back to infinity. Some participants question the assumptions made regarding the object's current location and its relation to the Earth's radius.

Discussion Status

The discussion is ongoing, with participants exploring the implications of gravitational potential and the work involved. Some guidance has been provided regarding the assumptions made, but no consensus or resolution has been reached.

Contextual Notes

There is an assumption that the object in question is a 5 kg mass located at the surface of the Earth, which may influence the calculations and reasoning discussed.

Bolter
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Homework Statement
Calculate the work done on the mass to a point where the gravitational potential is zero
Relevant Equations
V = –GM/r
Hi there

I have been attempting the parts to this question and I'm finding some trouble on how to answer the last part which is d)iii

IMG_3719.JPG


Here is what I have done for the rest of the parts and what I think I should start off with in part d)iii

IMG_3716.JPG

IMG_3717.JPG

IMG_3718.JPG


Thanks!
 
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Gravitational potential represents the work done (per kg) in order to bring the object from infinity to its current location.

1579894946508.png


By symmetry, the work to send the object back to infinity must be the same but of opposite sign.
 
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gneill said:
Gravitational potential represents the work done (per kg) in order to bring the object from infinity to its current location.

View attachment 256044

By symmetry, the work to send the object back to infinity must be the same but of opposite sign.

I see, this is what I have tried now

IMG_3720.JPG


Where I assumed that the current location of the 5 kg mass was lying at the surface of the Earth so the distance r was the radius of the Earth then
 
Given your assumption that looks good.
 

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