Work: Emptying a 2x1x1 box of water.

  • Thread starter Thread starter TylerH
  • Start date Start date
  • Tags Tags
    Box Water Work
Click For Summary
SUMMARY

The work required to empty a 2x1x1 ft box of water, given the density of water as 62.5 lb/ft³, is calculated using the integral formula \int_a^b A(x)xdx. The area function A(x) is determined to be 2, leading to the calculation of 62.5 times the integral from 0 to 1 of 2x, resulting in a total work of 62.5 lb-ft. The discussion emphasizes understanding the setup of such problems through the concept of summing small slices of water rather than memorizing formulas.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with the concept of work in physics
  • Knowledge of density and its application in volume calculations
  • Ability to set up and evaluate definite integrals
NEXT STEPS
  • Study the application of integrals in calculating work done against gravity
  • Learn about the concept of Riemann sums and their relation to integrals
  • Explore problems involving varying cross-sectional areas in fluid dynamics
  • Investigate the principles of hydrostatics and buoyancy
USEFUL FOR

Students studying calculus, physics enthusiasts, and educators looking to enhance their understanding of work calculations involving fluids.

TylerH
Messages
729
Reaction score
0

Homework Statement



How much work is required to empty a 2x1x1 ft box of water? Assume density of water is 62.5 lb/ft3.

Homework Equations



\int_a^b A(x)xdx
A(x)=lw=2

The Attempt at a Solution



62.5\int_0^1 2xdx=125\left[ \frac{x^2}{2} \right]_0^1=62.5

Did I get it right?
 
Physics news on Phys.org
looks good to me. Although if I were to give advice, I would say don't try to memorize those kinds of formulas. Instead, try to remember a method for setting these types of problems up. Usually this involves some form of considering a small "slice" of water of width \Delta x and finding the small amount of work \Delta W and then summing up over the entire volume of the water.
this method might seem tedious for simple problems, but it might give you a better understanding of what is really going on here.
 
Yeah, I know exactly what you mean. The whole point of covering work is to solidify the concept of the integral being an infinite sum of infinitesimals. I didn't show or explain my derivation, but I didn't memorise the formula, as it appears.

I was just wondering, because this was a question on a test and I was beginning to believe I missed it. I'll see for sure tomorrow (Monday).
 

Similar threads

Replies
1
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
20K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K