Work energy principle and power

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SUMMARY

The discussion focuses on applying the work-energy principle to determine the speed of a box sliding down a ramp. The ramp has a height of 20 cm and a length of 2.5 m. Using the conservation of energy, the gravitational potential energy (GPE) at the top is calculated as m × 10 × 0.2, which equals the kinetic energy (KE) at the bottom, expressed as 1/2mv². The final speed of the box when it reaches the bottom of the ramp is conclusively determined to be 2 m/s.

PREREQUISITES
  • Understanding of gravitational potential energy (GPE)
  • Knowledge of kinetic energy (KE) concepts
  • Familiarity with the conservation of energy principle
  • Basic algebra for solving equations
NEXT STEPS
  • Study the work-energy theorem in classical mechanics
  • Learn about different forms of energy and their conversions
  • Explore examples of energy conservation in various physical systems
  • Investigate real-world applications of the work-energy principle
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding energy conservation principles in motion scenarios.

Shah 72
MHB
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A box slides down a smooth ramp. The height of the ramp is 20cm and the length of the ramp is 2.5m. The box starts from rest. What is the speed of the box when it reaches the bottom of the ramp?
I don't understand how to solve this. Pls help
 
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We can apply conservation of energy.

What is the energy due to gravity at the beginning?
What is the kinetic energy at the end?
 
Increase in KE= loss of GPE
1/2mv^2= mgh
So gpe at the top = m×10× 0.2
GPE at the bottom = 0J
 
Klaas van Aarsen said:
We can apply conservation of energy.

What is the energy due to gravity at the beginning?
What is the kinetic energy at the end?
I don't understand how to solve this. Pls help
 
You have the correct equation.
Fill in g and h.
And we can cancel m from both sides.
 
Klaas van Aarsen said:
You have the correct equation.
Fill in g and h.
And we can cancel m from both sides.
h=0.2m, so v= 2m/s. I was getting confused with the length of the ramp.
Thanks a lottt!
 

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