Work & Energy: Solving Problems with v0, k, m, g

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SUMMARY

The discussion focuses on solving physics problems related to work and energy using variables such as initial velocity (v0), spring force constant (k), mass (m), and gravity (g). The participants explore various equations to determine displacement (x) based on these parameters. Key equations include x = v0*sqr((mg)/k) and x = v0^2/(2g), which utilize conservation of energy principles to relate kinetic and potential energy. The conversation emphasizes the importance of understanding these relationships for accurate problem-solving in physics.

PREREQUISITES
  • Understanding of basic physics concepts, particularly work and energy.
  • Familiarity with variables: initial velocity (v0), spring force constant (k), mass (m), and gravity (g).
  • Knowledge of mathematical operations including square roots and algebraic manipulation.
  • Experience with conservation of energy principles in physics.
NEXT STEPS
  • Study the derivation of the equation x = v0*sqr((mg)/k) for practical applications.
  • Explore the implications of conservation of energy in mechanical systems.
  • Learn how to apply the spring constant (k) in real-world scenarios.
  • Investigate the relationship between mass (m) and gravitational force (g) in various contexts.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in applying work and energy concepts to solve practical problems in physics.

jrdwagas
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Need help on problem...See attachment

New on the topic and the SUB only knows as much as we do.
Might be a lot to cover, but thanks anyway. (Also, please explain if you can)

v0-intitial velocity
sqr-square root
k-spring force constant
g-gravity
m-mass

Choices
1. x = v0*sqr((mg)/k)

2. x = v0*m/(kg)

3. x = v0*(mg)/k

4. x = v0*sqr(k/(mg)

5. x = v0*k/(gm)

6. x = v0^2/(2g)

7. x = v0*sqr(m/k)

8. x = v0*sqr(k/m)

9. x = v0^2/(2m)

10. x = v0*(mk)/g
 

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  • 10-14-2010 5;51;35 PM.jpg
    10-14-2010 5;51;35 PM.jpg
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Use conservation of energy. All the kinetic energy of the block (1/2) mv^2 goes into potential energy of the spring (1/2)kx^2
 

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