Work Energy Theorem: Explaining Constant Force and Acceleration

Click For Summary
The discussion clarifies that a body can accelerate even when forces are constant, as long as the net force is not zero. It uses the example of a car experiencing a crosswind, illustrating that the crosswind does not impact the car's forward motion but contributes to the overall forces acting on it. According to Newton's laws, an object will continue in motion unless a force acts upon it, which can result in either positive or negative acceleration. The relationship between force, mass, and acceleration is defined by the equation F = m*a, indicating that acceleration is dependent on the net force divided by mass. Therefore, for acceleration to be zero, the total forces must balance out to zero.
Miike012
Messages
1,009
Reaction score
0
I posted a picture of the paragraph that I am confused about...

The following paragraph says the body accelerates even though the forces are constant...

can some one explain why the acceleration is not zero?
 

Attachments

  • Acceleration.jpg
    Acceleration.jpg
    7.9 KB · Views: 436
Physics news on Phys.org
Because the total forces don't equate to zero. Think about a car driving down the road(x), and you have a crosswind pushing you to the left(y). the cross wind doesn't affect the x distance. In this case your F1, F2, and F3 add together to create a constant of sigma F

Remember Newton's laws an object in motion will stay in motion, less something acts upon it to accelerate, or slow down said object. Acceleration can be positive, or negative.

Your force would have to equal out to zero for the acceleration to equal zero. Force is defined as Acceleration * mass

F=m*a getting acceleration by itself would equal F/m,or you could go for finding the mass = F/a
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
7
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
3K
Replies
18
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 23 ·
Replies
23
Views
2K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
17
Views
2K
Replies
11
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K