Work Energy Theorem: Explaining Constant Force and Acceleration

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SUMMARY

The discussion centers on the Work Energy Theorem, specifically addressing why acceleration is not zero when forces are constant. It clarifies that if the net force (sigma F) acting on an object is not zero, the object will continue to accelerate. The conversation emphasizes Newton's laws, particularly the relationship defined by the equation F = m*a, where force equals mass times acceleration. Understanding this relationship is crucial for grasping the dynamics of motion under constant forces.

PREREQUISITES
  • Newton's Laws of Motion
  • Understanding of Force, Mass, and Acceleration
  • Basic principles of the Work Energy Theorem
  • Vector analysis in physics
NEXT STEPS
  • Study the implications of Newton's Second Law (F = m*a) in various scenarios
  • Explore the concept of net force and its effect on motion
  • Investigate the Work Energy Theorem in different contexts
  • Learn about vector components in physics, particularly in relation to forces
USEFUL FOR

Students of physics, educators explaining dynamics, and anyone interested in understanding the principles of motion under constant forces.

Miike012
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I posted a picture of the paragraph that I am confused about...

The following paragraph says the body accelerates even though the forces are constant...

can some one explain why the acceleration is not zero?
 

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Because the total forces don't equate to zero. Think about a car driving down the road(x), and you have a crosswind pushing you to the left(y). the cross wind doesn't affect the x distance. In this case your F1, F2, and F3 add together to create a constant of sigma F

Remember Newton's laws an object in motion will stay in motion, less something acts upon it to accelerate, or slow down said object. Acceleration can be positive, or negative.

Your force would have to equal out to zero for the acceleration to equal zero. Force is defined as Acceleration * mass

F=m*a getting acceleration by itself would equal F/m,or you could go for finding the mass = F/a
 

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