(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A car of mass 900 kg accelerates up a slope. The velocity of the car at the bottom of the slope is 5 m/s. By the time the car reaches the top of the slope, its velocity is 15 m/s. The slope is 8m high from the ground and has a length (radius - angled length - not base) of 500m. The average frictional force experienced by the car between A and B is 50N.

Calculate: The total work done by the car's engine between the bottom and top of the slope.

2. Relevant equations

F = ma

m = mass in kilograms

a = acceleration in m/s

F = force in newtons

W = F x s

s = distance

W = work

3. The attempt at a solution

I am quite at a loss with this question but this is my attempt.

Fbottom = m x a = 900 x 5 = 4500N

Work (bottom) = f x s

= 4500 x 500 (slope is 500m)

= 2250000J

Ftop = F x ma

= 900 x 15

= 13500N

Work (top) = f x s

= 135000 x 500

= 6750000J

W (top) - W (bottom) = 450000J

I am sure that my answer is incorrect but I am unsure as to how to solve it and the memo is missing the answer, any help would be appreciated. Sorry for the n00b question! :)

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Work of a car's engine as it moves up a slope

**Physics Forums | Science Articles, Homework Help, Discussion**