(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 30 kg block is slid down an inclined plane 5 m long with a height of 3 m from the floor. If the force of friction is 50 N, find the work done by the friction and the final velocity at the end of the plane.

2. Relevant equations

W = F*d

mgh = (1/2)mv^2

3. The attempt at a solution

50 N * 5 m * cos(180) = -250 J

Incorrect

30 kg * 9.8 m/s^2 * 3 m = (1/2) * 30 kg * v^2

882 = 15*v^2

58.8 = v^2

v = 7.6681 m/s

Incorrect

I don't know how else to approach this.

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# Homework Help: Work, potential and kinetic energy help

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