Work, Power and Energy assignment marked wrong somehow? :(

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The discussion centers on a misunderstanding regarding the calculation of time in a Work, Power, and Energy assignment. The original poster struggles with the tutor's lack of explanation, particularly around the impact velocity and distance fallen. Key points highlight that using the distance fallen to calculate time is incorrect since the object does not fall at a constant speed. Instead, it is suggested to assume constant acceleration and utilize relevant equations that do not require time. The emphasis is on focusing on distance, speed, and acceleration for accurate results.
jordanbeaton
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Homework Statement
A press machine has a tooling mass of 42.5kg which falls from a height of 2.3 metres onto an aluminium alloy work piece. If the depth of indentation into the block is 8.25mm calculate the following:
a) KE at impact
b) the impact velocity
c) retarding force on the tool in producing the indentation
d) work done in producing the indentation (assuming the energy is exhausted)
Relevant Equations
potential energy (PE) = mgh
PE = KE (kinetic energy)
acceleration formula
time formula
velocity break down formula
All of my working out is attached with the photos, I'm struggling to do anymore as the tutor hasn't explained anything like this yet. Any help would be much appreciated
 

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It goes wrong when you calculate the time. First, what time did you want to calculate? The time to stop the tool, right? You used the velocity at impact, which is fine, but you used the distance it fell which has nothing to do with the deceleration at impact. Even if that had been the right distance, you can’t use d=v t. That is only true if the velocity is constant.

I believe what you want to do here is assume the acceleration is constant. Can you relate constant acceleration, initial velocity, distance, and time?
 
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The time to fall is wrong because it does not fall at constant speed. You know ##s=\frac12 a t^2 ## ?
But you don't need this. You've done a, b, now you're looking at the deceleration over the very short distance of the dent.

This will also not be constant speed.
Don't bother to work out the time - you don't need it - and there is an equation that doesn't involve time. Just use the distance, speed and acceleration.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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