Work, Power and Energy assignment marked wrong somehow? :(

Click For Summary
SUMMARY

The forum discussion centers on the miscalculation of time in a physics assignment related to work, power, and energy. The user incorrectly applied the formula d = vt, assuming constant velocity, which is not applicable in this scenario due to variable acceleration. Instead, the correct approach involves using the relationship between distance, speed, and acceleration without calculating time, particularly in the context of deceleration over a short distance. The discussion emphasizes the importance of understanding constant acceleration principles in physics.

PREREQUISITES
  • Understanding of basic physics concepts, particularly work, power, and energy.
  • Familiarity with kinematic equations, specifically those involving constant acceleration.
  • Knowledge of the relationship between distance, speed, and acceleration.
  • Ability to analyze motion under variable conditions rather than assuming constant velocity.
NEXT STEPS
  • Study the kinematic equations for motion under constant acceleration.
  • Learn how to apply the work-energy principle in physics problems.
  • Explore the concept of deceleration and its impact on motion calculations.
  • Review examples of variable acceleration scenarios in physics to enhance problem-solving skills.
USEFUL FOR

Students studying physics, particularly those tackling assignments related to work, power, and energy, as well as educators seeking to clarify concepts of motion and acceleration.

jordanbeaton
Messages
2
Reaction score
0
Homework Statement
A press machine has a tooling mass of 42.5kg which falls from a height of 2.3 metres onto an aluminium alloy work piece. If the depth of indentation into the block is 8.25mm calculate the following:
a) KE at impact
b) the impact velocity
c) retarding force on the tool in producing the indentation
d) work done in producing the indentation (assuming the energy is exhausted)
Relevant Equations
potential energy (PE) = mgh
PE = KE (kinetic energy)
acceleration formula
time formula
velocity break down formula
All of my working out is attached with the photos, I'm struggling to do anymore as the tutor hasn't explained anything like this yet. Any help would be much appreciated
 

Attachments

  • answer.jpg
    answer.jpg
    71.9 KB · Views: 226
  • question.jpg
    question.jpg
    59.5 KB · Views: 195
Physics news on Phys.org
It goes wrong when you calculate the time. First, what time did you want to calculate? The time to stop the tool, right? You used the velocity at impact, which is fine, but you used the distance it fell which has nothing to do with the deceleration at impact. Even if that had been the right distance, you can’t use d=v t. That is only true if the velocity is constant.

I believe what you want to do here is assume the acceleration is constant. Can you relate constant acceleration, initial velocity, distance, and time?
 
1582657946544.png

The time to fall is wrong because it does not fall at constant speed. You know ##s=\frac12 a t^2 ## ?
But you don't need this. You've done a, b, now you're looking at the deceleration over the very short distance of the dent.

This will also not be constant speed.
Don't bother to work out the time - you don't need it - and there is an equation that doesn't involve time. Just use the distance, speed and acceleration.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
1K
Replies
4
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
5
Views
2K
Replies
5
Views
1K