Can Work, Power, and Energy be Solved Together?

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SUMMARY

The discussion centers on the relationship between work, power, and energy in the context of friction affecting an object's motion. Participants clarify that when an object stops due to friction, it loses kinetic energy, which is converted into work done by friction. The potential energy (P.E.) lost is calculated as "mgh," where "m" is mass, "g" is gravitational acceleration, and "h" is height. The key takeaway is that energy is not entirely lost but transformed, and understanding the specific point of stopping is crucial for accurate calculations.

PREREQUISITES
  • Understanding of basic physics concepts such as work, energy, and power.
  • Familiarity with gravitational potential energy (P.E.) calculations.
  • Knowledge of friction's role in energy transformation.
  • Ability to interpret motion problems in physics.
NEXT STEPS
  • Study the principles of energy conservation in physics.
  • Learn about the work-energy theorem and its applications.
  • Explore the effects of friction on kinetic and potential energy.
  • Investigate real-world examples of energy transformation in mechanical systems.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of work, energy, and friction in mechanical systems.

thunderhadron
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Hi friend the problem is as such:


Attempt to the question:



Thank you all in advance.
 
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If the object stops because of friction, does it have any energy left? So how much work was done by friction?
 
voko said:
If the object stops because of friction, does it have any energy left? So how much work was done by friction?

If the body comes to the bottom of the hill. Then total P.E. "mgh" will be lost due to friction. But The question doesn't state that that the body has come to the bottom of the hill.

Its saying about any arbitrary point on the path midway. Am I taking it in wrong manner?
 
The problem says it slides down and then stops somewhere in the horizontal path. How do you interpret that?
 
Ok then 2mgh. I got it. Thanks for the help voko.
 
Thank you very much friends. I got the answer. Problem has been cleared.
 

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