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Introductory Physics Homework Help
Work problem, box moves at h=.25 with F=85N
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[QUOTE="edgarpokemon, post: 5468076, member: 586959"] [h2]Homework Statement [/h2] A constant force Fa of magnitude 85.0N is applied to a 3.0kg shoe box at angle 55.0, causing the box to move up a frictionless ramp at constant speed. How much work is done on the box by Fa when the box has moved through vertical distance h=.25m? [h2]Homework Equations[/h2] mgsin(angle)-Fa=0(constant speed) mgsin(55)=Fa=24.08N hyp=opp/sin(55)=.305m Work=+7.35J (problably minus because the work is pointing down and displacement is up) mgh=-7.35J [h2]The Attempt at a Solution[/h2] So I know that the simple way is just to use mgh. But in my homework the the box is going up, so I assume that the gravity will do negative work. But the answer is positive and they used mgh. They used Wa=-Wg and they they switched the -Wg to +Wg, and i am not sure why they did that. So was what I did correct too? [/QUOTE]
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Introductory Physics Homework Help
Work problem, box moves at h=.25 with F=85N
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