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Introductory Physics Homework Help
Work problem, box moves at h=.25 with F=85N
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[QUOTE="BvU, post: 5468160, member: 499340"] Hello Ed, I don't see ##m\vec g\sin\theta## and ##\vec F_a## pointing in the same direction ? I agree that the component of ##\vec F_a## along the incline should be 24.1 Newton (my ##|\vec g| = 9.81## m/s[SUP]2[/SUP]). And if ##\vec F_a## does no work perpendicular to the incline (there is no displacement in that direction), but only along the incline, over the given distance, I get a different result ! [edit] I suspect this exercise is a lot more involved then you (and I at first) think. Where in the drawing is the ##55 \ ^\circ## ? Is ##\phi = 55^\circ##. In that case: check: "frictionless" and "at constant speed" ! [edit2] suspicion relieved, see below o:) . And I don't get a different answer any more . But ##Fa## is an unknown. [/QUOTE]
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Introductory Physics Homework Help
Work problem, box moves at h=.25 with F=85N
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