Work required to disassemble a helium atom

[tevatron1]

Homework Statement

A helium atom has a rest mass of He = 4.002603u. When disassembled into its constituent particles (2 protons, 2 neutrons, 2 electrons), the well-separated individual particles have the following masses: p = 1.007276u, n= 1.008665u, e = 0.000549u.

How much work is required to completely disassemble a helium atom? (Note: 1 u of mass has a rest energy of 931.49 MeV.)

Homework Equations

E=mc^2

The Attempt at a Solution

2(1.007276u + 1.008665u + 0.000549u) = 4.03298u

4.03298u - 4.002603u = .030377u

E = (0.030377u)*(931.49 MeV/u)*(3.0*10^8)^2

E = 2.5466*10^18 MeV

*I tried using c = 2.9979*10^8, however it is still wrong.

 

[Office_Shredder]

Did you notice that the units of (0.030377u)*(931.49 MeV/u)*(3.0*10^8)^2 are m⁴/s⁴?

The conversion 931.49 MeV/u is not a conversion between one mass and another mass, so multiplying by this and then using E=mc² afterwards is pretty suspect

 

[tevatron1]

Did you notice that the units of (0.030377u)*(931.49 MeV/u)*(3.0*10^8)^2 are m⁴/s⁴?

The conversion 931.49 MeV/u is not a conversion between one mass and another mass, so multiplying by this and then using E=mc² afterwards is pretty suspect

I had considered this. I'm honestly not sure where else to use the conversion. Can you give a hint? Am I correct to solve for the change in mass?