Work required to move capacitor plates

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SUMMARY

The discussion focuses on calculating the work required to move the plates of an ideal parallel plate capacitor from a separation distance of D to an integer multiple of D, with the area of each plate denoted as A. The key equations referenced include the force between the plates, F = q² / (2ε₀A), and the potential energy stored in the capacitor, U = (1/2)CV². Participants emphasize the need for an integral approach to determine work, W = ∫F dr, and the importance of considering whether the capacitor is charged and connected to a battery, as this affects charge (Q) and voltage (V) relationships.

PREREQUISITES
  • Understanding of electric fields and forces between capacitor plates
  • Familiarity with the equations for potential energy in capacitors
  • Knowledge of integral calculus for evaluating work done
  • Concept of charge conservation in capacitors connected to a battery
NEXT STEPS
  • Study the derivation of the work done in moving capacitor plates using integral calculus
  • Explore the relationship between charge (Q), voltage (V), and capacitance (C) in different configurations
  • Learn about energy density in electric fields and its application in capacitor problems
  • Investigate the implications of connecting and disconnecting capacitors from power sources
USEFUL FOR

Students in physics or electrical engineering, particularly those studying electromagnetism and capacitor behavior, as well as educators seeking diverse methods for teaching capacitor work calculations.

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Homework Statement



Determine the work required to move the plates of an ideal parallel plate capacitor from a separation distance of D to an integer multiple of D, (assume only one moves for simplicity). The each plate has an area A.

Homework Equations


F = q^2 /( 2 e_0 A) field strength between the plates
\Delta V = U/q
\DeltaU = -W
\DeltaV= Qd/e_0 A



The Attempt at a Solution



moving the terms above around I came up with U = Qdq/e_0A
I know I need an integral here, probably evaluated between D and multiple of D(its a general solution that's needed)
Am I on the right track?
 
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Though it's a little cheap and probably not what your professor had in mind, you can use the equation for energy density(J/m^2) stored in an electric field to solve this problem. Do final energy stored minus initial energy stored to calculate what energy was added (or done) to the system.
 
I appreciate the reply. I thought about that, but I use that in another part of the problem, not that I can't use it again since its different variables, but I am fairly certain I'll be graded on the diversity of methods used.

Anyone know if that integral approach would work or am I grasping at fog?
 
Why not use the appropriate equation for energy stored in a capacitor?
 
well since you know the force between the two plates

Work is

W=Integral (Fdr)
 
Thats what I thought but I encounter a problem, when I compare the integral result to one obtained by use of potential energy, I am getting a different result depending on different terms. Considering that the work should be the same, I am stuck. Is there anyway Q^2= Vbat?
 
In the question has the capacitor been charged and disconnected from the battery?If so Q remains constant and V changes if the plate separation is changed.If the capacitor remains connected to the battery V remains constant and Q changes.
 
Also remember the potential energy of a system is (CV^2)/2
 

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