Work vs Volume: Trig Integral Relation

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SUMMARY

The discussion centers on the relationship between work integrals and the volume of a 4-ball, specifically using the method of cylindrical shells. The speaker highlights that the work integral for pumping liquid from a hemispherical tank can be directly related to the volume calculation of a 4-ball, leading to the formula for the volume of a 4-ball of radius 'a' as (π²)(a⁴)/2. This connection, while mathematically sound, appears to have been overlooked in current calculus texts and may not have been recognized even by historical figures like Archimedes.

PREREQUISITES
  • Understanding of integral calculus, specifically work integrals.
  • Familiarity with the method of volumes by slicing.
  • Knowledge of cylindrical shells method for volume calculation.
  • Basic concepts of higher-dimensional geometry, particularly 4-dimensional volumes.
NEXT STEPS
  • Explore the method of volumes by slicing for calculating higher-dimensional volumes.
  • Study the cylindrical shells method in detail for volume integrals.
  • Research historical perspectives on volume calculations in mathematics, focusing on Archimedes' contributions.
  • Investigate the applications of work integrals in physics and engineering contexts.
USEFUL FOR

Mathematics students, educators teaching calculus, and anyone interested in the connections between physical concepts of work and geometric volume calculations.

mathwonk
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A few years ago I challenged my class to use the method of volumes by slicing to
compute the volume of a 4 ball,

knowing the volume of a 3-ball. This leads to a slightly challenging trig
integral, but not out of reach for a strong

calculus student. (no one did it however.)

This Fall while teaching the concept of work, I noticed the work integral for
pumping liquid from a tank,

is just the "cylindrical shells" integral for 4 dimensional volume (except for
the factor of 2 pi).

So if they have computed the relatively easy integral of work

to empty a unit radius hemispherical tank of unit density liquid as pi/4,

it follows that the volume of a 4 ball of radius a, is (2pi)(pi/4)a^4 = (pi)^2
(a^4)/2.

Is this a standard observation?
 
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so as far as we know, nobody has noticed this rather obvious fact for the last 2000 years?

i am not sure actually archimedes did not know this, but it seems to escape current calc texts.
 
in case you have not done this calculation, using slices means you have to integrate an odd power of (a^2 - x^2)^(1/2) to do even dimensional ball volumes, while using shells yields an even power.
 

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