Working of Van De Graff generator

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SUMMARY

The Van de Graaff generator operates by using a high-voltage power supply to create a strong electric field, which causes dielectric breakdown of air and transfers positive charge to an insulated belt. The power supply continuously replenishes the positive charge on the conductor, despite the apparent discontinuity in the circuit path. The flow of electricity moves from the power supply to the discharge electrode, up the belt to the top-load sphere, and discharges into the air, completing the circuit through the ground connection. This system can be modeled as a capacitor, where the top-load acts as one plate and the ground as the other, resulting in periodic discharges.

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akhil123
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In a Van de graff generator, the positive conductor which is connected to the power supply (of high voltage) generates an electric field of high value, which results in dielectric breakdown of air and the positive charge gets "transferred" to the insulated belt. The book says " positive charge is replenished on the conductor by the power supply". My question is, if the path is discontinuous, how can battery replenish the charge? Some positive charge from the negative conductor should flow back to the battery to happen.
 
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You have to think about the full path of the flow of electricity.

It flows from the power supply to the discharge electrode, up the belt to the top-load (sphere). Then it either leaks or is discharged as a spark into the surrounding air and back to ground.

The other side of the power supply is connected to ground, which completes the circuit.

In electrical circuit theory, the top-load would be seen as one plate of a capacitor, the other being the ground. In this case the capacitor periodically flashes over.
 

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