Working out a point / segment on a sphere

  • Level: Graduate 
  • Thread starter rede96
  • Start date
  • Tags Tags
    Point Sphere
3 replies · 2K views · last reply
rede96
Messages
663
Reaction score
16
Hi, I was hoping someone could help me figure out the problem below. It is a bit of a long winded questions so please bare with me!

If you look at Fig 1 below, I have a sphere that spins about an axis in a clockwise direction. (the direction of the spin doesn't really matter) In this case the axis is pointing directly upwards, so the angle is 0 degrees.

You will notice the sphere also has a shaded area which covers the top half of the sphere.

If a put a 'segment line' perpendicular to the axis, which is at a distance x from the centre line, it will intersect the surface of the sphere at 2 points which I have labelled a1 and a2.

I know that as long as I place the segment line above the centre line then points a1 and a2 will always be in the shaded area as the sphere rotates.
Diagram of a sphere with a vertical axis labelled 0°, a shaded top half, a horizontal centre line, and a segment line at distance x above it meeting the surface at points a1 and a2; an arrow shows clockwise spin.

Now if I turn the axis by 90 degrees as in Fig 2 below, I can put a segment line at any distance x from the centre line, perpendicular to the axis, and points a1 and a2 will spend 50% of the time in the shaded area and 50% of the time in the unshaded area, as the shaded area doesn't rotate with the axis.
Diagram of a circle with its top half shaded green, labelled Centre Line (vertical), Segment Line (horizontal arrow to the right of the centre line), points a1 and a2 on the circle, distance x, angle θ, and 90° marked on a horizontal axis.

So, I now turn the axis to 60 degrees as in Fig 3 below and I want to know at what distance x would the segment line need to be away from the centre line so points a1 and a2 would always be in the shaded area as the sphere turns.

I can do a bit of trig here and make a right angled triangle between the centre point of the circle, point a2 and the point where the segment line intersects the axis. I know the angle is 30 degrees and I know the radius r, so Cos 30 r = x

Diagram of a sphere shown as a circle with its top half shaded green, a centre line tilted at 60 degrees, a segment line at distance x above the centre, points a1 and a2 where it meets the sphere, angle theta, and a rotation arrow.


In Fig 4 below the axis is again at 60 degrees. My question is at what distance x from the centre line would I need to place the segment line so points a1 and a2 would spend 75% of the time in the shaded area and 25% of the time in the unshaded area as the sphere rotates. I just can't figure this out!

Any help would be much appreciated.

Diagram of a sphere with a shaded upper cap, a centre line tilted at 60 degrees, a segment line at distance x from the centre, and points a1 and a2 where the segment meets the surface; a curved arrow shows rotation.
 
Last edited:
I would suggest starting with a picture of the circle a1 and a2 trace out in their rotation. Consider where the shaded region will fall depending on your variable, then find the cutoff line which divides the circle into parts of 1/4:3/4.
 
rede96 said:
Hi, I was hoping someone could help me figure out the problem below. It is a bit of a long winded questions so please bare with me!

Sorry, I never disrobe with strangers.
 
LCKurtz said:
Sorry, I never disrobe with strangers.
haha :) Don't blame you!

RUber said:
would suggest starting with a picture of the circle a1 and a2 trace out in their rotation. Consider where the shaded region will fall depending on your variable, then find the cutoff line which divides the circle into parts of 1/4:3/4.

Thanks for the reply but to be honest I’m not sure how that will solve it?

On the sphere, where the line a1,a2 crosses the diameter of the shaded area, (the line that runs horizontally across the middle of the circle) let’s call that point a3.

I know that I can split any circle into 1/4:3/4 easily enough, it is just 90 degrees and 270 degrees along the circumference. This would be equivalent to the path a1 and a2 take. I also know that if I draw a line across any of the quadrants of that circle, the mid-point of that line that must intersects point a3 on the sphere.

But what I have no way of knowing (Or haven’t figured it out yet!) is how big the diameter a1,a2 must be so when that circle a1, a2 sits in the sphere it fits in the right place for a1 and a2 to travel around the sphere in the shaded area 75% and non shaded 25%

Anyway, up for work early, so will try and give it some more through during the week.
 
Attachments
  • A single lowercase letter x.
    upload_2015-3-15_21-36-1.png
    220 bytes · Views: 632