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Working with degrees instead of radians

  1. Oct 28, 2011 #1
    1. The problem statement, all variables and given/known data

    If x is measured in radians, then the derivative of Sin[x] with respect to x is Cos[x].

    Use the formula Sin [x degrees] = Sin [2π/360 x radians]
    to calculate the derivative of Sin [x degrees] with respect to x.

    Why does the resulting formula make calculus difficult if you insist on working with degrees instead of radians?

    Thanks for any help you can offer!

    2. Relevant equations
    y = sin [πx/180]
    y' = 1/180 * π * cos[πx/180]

    3. The attempt at a solution
    I don't understand the "Why does the resulting formula make calculus difficult if you insist on working with degrees instead of radians?" question.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 28, 2011 #2

    LCKurtz

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    Don't you think that having a pi/180 nuisance factor in all derivatives of the trig functions qualifies as a reason?
     
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