1. Oct 28, 2011

### cornelius bay

1. The problem statement, all variables and given/known data

If x is measured in radians, then the derivative of Sin[x] with respect to x is Cos[x].

Use the formula Sin [x degrees] = Sin [2π/360 x radians]
to calculate the derivative of Sin [x degrees] with respect to x.

Why does the resulting formula make calculus difficult if you insist on working with degrees instead of radians?

2. Relevant equations
y = sin [πx/180]
y' = 1/180 * π * cos[πx/180]

3. The attempt at a solution
I don't understand the "Why does the resulting formula make calculus difficult if you insist on working with degrees instead of radians?" question.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Oct 28, 2011

### LCKurtz

Don't you think that having a pi/180 nuisance factor in all derivatives of the trig functions qualifies as a reason?