What is the minimum work needed to push a 1000 kg car up 45.0 meters up a 12.5 [tex]\circ[/tex] degree incline?(adsbygoogle = window.adsbygoogle || []).push({});

a. Ignore Friction

b. Assume the effective coefficient of friction is 0.30.

Work: W = (F*d)cos[tex]\theta[/tex]

Coefficient of friction: W = [tex]\mu[/tex]N(d)

What I did: W = (m*g)(d)cos[tex]\theta[/tex]. (1000kg)(9.8m / s^2)(45.0m)cos(102.5)

= -95449.9 J = 9.5 X 10^4 J work done to push the car up.

Then, the work friction is doing to car:

W = 0.30(1000kg*sin(12.5)*9.8 m/s^2)(45m)? This is where I get stuck because I know work done by friction on ramp is [tex]\mu[/tex]*normal force*displacement...

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# Homework Help: Works with coefficient of friction

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