Would the precipitate be Copper II Chloride in this chemical equation?

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The chemical equation 3 CuCl2 + 2Al + HCl → 2 AlCl3 + HCl + 3Cu indicates that the precipitate formed is indeed Copper II Chloride (CuCl2), despite initial confusion regarding its solubility. The discussion clarifies that the presence of solid copper suggests a reduction reaction, while the net ionic equation must account for all charges, confirming that ions do not cancel out. Participants emphasized the importance of correctly identifying ionic species in the reaction.

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3 CuCl2 + 2Al + HCL →2 AlCl3 + HCL + 3Cu

I'm think it's Copper II Chloride because the Copper is a solid, but the solubility rules with the Cl would suggest otherwise. What would be the precipitate here? One other would the net ionic equation have no reaction, since the ions cancel on both sides??
 
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Ions don't cancel, apparently you have no idea what is ionic here.

Try to write net ionic equation - don't forget to put all charges there.
 

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