Write 1-2i in Polar Form - Solve Confusion

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To write the complex number 1-2i in polar form, the modulus is calculated as r=√5. The angle can be determined using the arctangent function, considering the signs of the real and imaginary parts to identify the correct quadrant. The angle is found to be either 63.43° or 296.57°, with the latter being the correct representation in the fourth quadrant. It's important to track the signs of the numerator and denominator when using the arctangent to ensure the angle is placed accurately. This approach clarifies the confusion surrounding the polar form conversion.
dylanhouse
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Homework Statement



How do I write 1-2i in polar form?

Homework Equations





The Attempt at a Solution



I know r=√5, and when using x=rcosθ, I get angle of 63.43 or 296.57. However, when I take the sin inverse of-2/√5 I get -63.43. I am really confused.
 
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dylanhouse said:

Homework Statement



How do I write 1-2i in polar form?

Homework Equations





The Attempt at a Solution



I know r=√5, and when using x=rcosθ, I get angle of 63.43 or 296.57. However, when I take the sin inverse of-2/√5 I get -63.43. I am really confused.
The angle is in the 4th quadrant, so it would be either -63.43° or +296.57° (assuming your figures are correct.
 
dylanhouse said:

Homework Statement



How do I write 1-2i in polar form?

Homework Equations





The Attempt at a Solution



I know r=√5, and when using x=rcosθ, I get angle of 63.43 or 296.57. However, when I take the sin inverse of-2/√5 I get -63.43. I am really confused.

The formula is arc tan (Im part)/(Real part). You need to keep track of the numerator and denominator signs to make sure you land in the correct quadrant. In other words, the fact that the I am is - and the Re is + tells you which quadrant to land in.
 
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