captainjack2000 said:
I then say that an object does not need to be rotating about an origin to have angular momentum. Is this right. Does it just have to been moving at a changing angle wrt to a point? If I then say L=m(rxv) is that the best way to explain angular momentum?
HELP
Angular momentum is defined as the cross product of the position vector and linear momentum of a particle as you stated:
[tex]\vec{L} = \vec{r} \times \vec{p}[/tex]
The angular momentum of a particle is dependent upon where we place the origin of our system; as the origin is moved closer to the particle, the magnitude of [tex]\vec{r}[/tex] becomes smaller, and as a consequence, the magnitude of the angular momentum becomes smaller as well for the same linear momentum [tex]\vec{p}[/tex]. An alternative definition is
[tex]L = rpsin\theta[/tex]
where [tex]\theta[/tex] is the angle between the position and linear momentum vectors.
Yes, you are right the object does not necessarily need to be rotating about the origin to have angular momentum.
What is the nature of your class? Have they any knowledge of angular momentum, or even linear momentum? Please don't take offense, but it appears that you want to give a comprehensive yet short discussion on these topics and with some mathematical rigor. Will the kids need these equations in the near future? Perhaps, intuitive examples from everyday experience will be better oriented towards your audience? Good luck.