Write the electron configuration of Cd2+

[jupiter_8917]

Write the electron configuration of Cd2+

Is It right if I write it like this 1s^2 2s^2 2p^6 3s^1 3p^6 3d^10 4s^2 4p^6 5s^2 4d^10?

Can anyone please correct me if it is wrong? Thank you very much!

 

[Borek]

5s²4d¹⁰ looks to me like neutral atom, not a cation.

Why 3s¹? Is it just a typo?

 

[lucky_star]

Hi,
In order for Cd to form Cd²⁺, Cd has to lose its 2e^- in the outer-shell. So, take a look at your configuration, you are having the configuration for the neutral Cd, you need to remove 2 outer e^- to get the right configuration. And also don't forget the "reminder" from Mr. Borek about the 3s¹ typo.

Good Luck!

 

[jupiter_8917]

do you mean it need to be like this in order to form Cd2+? 1s^2 2s^2 2p^6 3s^1 3p^6 3d^10 4s^2 4p^6

thanks again,

 

[Borek]

Sorry for the confusion. Electron configuration of Cd can be given as [Kr]5s²4d¹⁰ - that is very convenient short hand notation, that uses noble gas configuration as its basis. Configuration of Kr is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶, so [Kr]5s²4d¹⁰ means 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰ - that's configuration of neutral Cd atom. I was referring to this notation and just to the last two subshells.

[Kr]5s²4d¹⁰ is a configuration of the neutral atom. As it was said several times - to make Cd²⁺ you have to remove two electrons.