MHB Write the piecewise function in terms of unit step functions.

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The piecewise function is expressed in terms of unit step functions as follows: f(t) = 2t[u(t) - u(t-3)] + 6[u(t-3) - u(t-5)] + 2t[u(t-5)]. The original function consists of three segments defined over different intervals. The first segment is active from t = 0 to t = 3, the second from t = 3 to t = 5, and the third for t ≥ 5. The provided formulation captures these transitions using the unit step function effectively. This representation allows for a clear understanding of the piecewise behavior of the function.
shamieh
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Write the piecewise function
\[ f(t) = \begin{cases}
2t, & 0\leq t < 3 \\
6, & 3 \le t < 5 \\
2t, & t \ge 5 \\
\end{cases}
\]
in terms of unit step functions.

So here is what i;ve got just guessing , I don't think I'm correct. I really need some help. But I got:

$f(t) = 2t[u(t-0) - u(t-3)] + 6[u(t-3) - u(t-5)] + 2t[u(t-5) - u(t - \infty)]$

Which becomes

$f(t) = 2t[u(t) - u(t-3)] + 6[u(t-3) - u(t-5)] + 2t[u(t-5)]$
 
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Looks good to me!
 

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