Write the piecewise function in terms of unit step functions.

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SUMMARY

The piecewise function \( f(t) \) defined as \( f(t) = \begin{cases} 2t, & 0\leq t < 3 \\ 6, & 3 \le t < 5 \\ 2t, & t \ge 5 \end{cases} \) can be expressed using unit step functions. The correct formulation is \( f(t) = 2t[u(t) - u(t-3)] + 6[u(t-3) - u(t-5)] + 2t[u(t-5)] \). This representation accurately captures the behavior of the function across its defined intervals.

PREREQUISITES
  • Understanding of piecewise functions
  • Familiarity with unit step functions (Heaviside function)
  • Basic knowledge of mathematical notation and functions
  • Experience with function transformations
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  • Study the properties and applications of unit step functions
  • Learn how to derive piecewise functions using Laplace transforms
  • Explore advanced topics in signal processing related to step functions
  • Practice writing and manipulating piecewise functions in different contexts
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shamieh
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Write the piecewise function
\[ f(t) = \begin{cases}
2t, & 0\leq t < 3 \\
6, & 3 \le t < 5 \\
2t, & t \ge 5 \\
\end{cases}
\]
in terms of unit step functions.

So here is what i;ve got just guessing , I don't think I'm correct. I really need some help. But I got:

$f(t) = 2t[u(t-0) - u(t-3)] + 6[u(t-3) - u(t-5)] + 2t[u(t-5) - u(t - \infty)]$

Which becomes

$f(t) = 2t[u(t) - u(t-3)] + 6[u(t-3) - u(t-5)] + 2t[u(t-5)]$
 
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Looks good to me!
 

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