Write the Standard Form of the Equation for this Circle

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Homework Help Overview

The discussion revolves around writing the standard form of the equation for a circle given the endpoints of its diameter, specifically the points (11, −5) and (3, 15).

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the steps to find the radius and the center of the circle using the midpoint formula and the distance formula. Questions arise about how to determine the center coordinates (h, k) from the endpoints of the diameter.

Discussion Status

There is ongoing exploration of the relationship between the midpoint of the diameter and the center of the circle. Some participants suggest drawing the points on a graph to aid understanding, while others express confusion about the follow-through in the problem-solving process.

Contextual Notes

Participants mention the need to calculate the radius using the distance formula after determining the midpoint. There is a sense of urgency in some responses regarding the importance of following through with the problem-solving steps.

nycmathguy
Homework Statement
Write standard form of the equation of a circle.
Relevant Equations
Equation of a circle not centered at the origin.

(x - h)^2 + (y - k)^2 = r^2
Chapter 1, Section 1.2

Write the standard form of the equation of the circle with the given characteristics.

74. Endpoints of a diameter: (11, −5), (3, 15)

I want to know if the following steps are correct for me to answer the above question.

Steps:

1. Find the distance between the points.

2. Divide the distance by 2 to find the radius.

3. Plug into (x - h)^2 + (y - k)^2 = r^2

You say?
 
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nycmathguy said:
Homework Statement:: Write standard form of the equation of a circle.
Relevant Equations:: Equation of a circle not centered at the origin.

(x - h)^2 + (y - k)^2 = r^2

Steps:

1. Find the distance between the points.

2. Divide the distance by 2 to find the radius.

3. Plug into (x - h)^2 + (y - k)^2 = r^2
Looks reasonable so far, but how do you use those two endpoints to find h and k? :smile:
 
Do you know the midpoint formula?
 
cbarker1 said:
Do you know the midpoint formula?

Yes, I know the midpoint formula. What about it?
 
berkeman said:
Looks reasonable so far, but how do you use those two endpoints to find h and k? :smile:
I would plug the x and y values of the endpoints in the standard form of an equation of a circle to find h and k. Yes?
 
nycmathguy said:
I would plug the x and y values of the endpoints in the standard form of an equation of a circle to find h and k. Yes?
Sorry, I have no idea what that means. Instead, I would follow this hint:
cbarker1 said:
Do you know the midpoint formula?
 
nycmathguy said:
You say?
I say that once again, you are not following through.

Draw the two points on a graph. Calculate the midpoint numerically and see if it looks right on the graph. When you have the midpoint, write the equation of the circle. There's more for a full follow-through.
 
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nycmathguy said:
Yes, I know the midpoint formula. What about it?
How is the mid-point of a diameter of a circle related to the location of the circle's center ?
 
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nycmathguy said:
Yes, I know the midpoint formula. What about it?
So what is the formula, then?
 
  • #10
SammyS said:
How is the mid-point of a diameter of a circle related to the location of the circle's center ?

The midpoint of a circle divides the diameter into two radii.
 
  • #11
nycmathguy said:
The midpoint of a circle divides the diameter into two radii.
I asked about the mid-point of a diameter of a circle. How is the mid-point related to the center of the circle?
 
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  • #12
nycmathguy said:
The midpoint of a circle divides the diameter into two radii.
Quite futzin' around just DRAW it and get on with solving the problem. I don't understand why you have such an issue with follow through. You are going to keep having trouble with these problems if you don't get past that issue.
 
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  • #13
phinds said:
Quite futzin' around just DRAW it and get on with solving the problem. I don't understand why you have such an issue with follow through. You are going to keep having trouble with these problems if you don't get past that issue.
Follow through in what way? I'm stuck here.
 
  • #14
SammyS said:
I asked about the mid-point of a diameter of a circle. How is the mid-point related to the center of the circle?

Midpoint = [(11 + 3)/2, (-5 +15)/2]

Midpoint = (14/2, 10/2)

Midpoint = (7, 5)

This point = (h, k) = (7, 5).

So, h = 7 and k = 5.

I now plug into (x - h)^2 + (y - k)^2 = r^2.

Wait, I need the radius.

To find the radius, I must use the distance formula points.

So far, so good, yes?
 
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  • #15
phinds said:
Quite futzin' around just DRAW it and get on with solving the problem. I don't understand why you have such an issue with follow through. You are going to keep having trouble with these problems if you don't get past that issue.

I found h to 7 and k to be 5.

My friend completed the problem.

Here is her work:

distance between center (7,5) and point (3, 15) is the length of radius:

r=sqrt((7-3)^2+(5-15)^2)
r=sqrt(4^2+(-10)^2)
r=sqrt(16+100)
r=sqrt(116)

then r^2=116
(x - 7)^2 + (y - 5)^2 = 116=> your equation
 
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  • #16
nycmathguy said:
Follow through in what way? I'm stuck here.
Do you not understand how to put points on a graph?
 
  • #17
phinds said:
Do you not understand how to put points on a graph?
Forget it. Problem has been solved.
 
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