Changing standard form to slope intercept form.

Kirito123
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Homework Statement


Write the equation 4x – 7y – 14 = 0 in the form y = mx + b.

Homework Equations


"Y= mx + b" and "standard form".

The Attempt at a Solution

4x – 7y – 14 = 0 (add 14 to both sides of the equation)

4x – 7y = 14 (subtract 4x from both sides of the equation)

-7y = -4x + 14 (divide both sides of the equation by -7)

y = -4x/-7 + 14/-7

y = 4/7x + (-2)

so the slope (m) is 4/7 and the initial value (b) is -2Is this the correct way to answer this question. thanks for your time to help me :)
 
on Phys.org
Kirito123 said:

Homework Statement


Write the equation 4x – 7y – 14 = 0 in the form y = mx + b.

Homework Equations


"Y= mx + b" and "standard form".

The Attempt at a Solution

4x – 7y – 14 = 0 (add 14 to both sides of the equation)

4x – 7y = 14 (subtract 4x from both sides of the equation)

-7y = -4x + 14 (divide both sides of the equation by -7)

y = -4x/-7 + 14/-7

y = 4/7x + (-2)

so the slope (m) is 4/7 and the initial value (b) is -2Is this the correct way to answer this question. thanks for your time to help me :)

Correct, well done
 
Thank you a lot. Now I know I'm doing it the correct way :)
 
Kirito123 said:
...

so the slope (m) is 4/7 and the initial value (b) is -2

Is this the correct way to answer this question. thanks for your time to help me :)
We usually refer to b as the y-intercept rather than the initial value.
 
At the start you could have saved at least one operation by adding 7y to both sides.
 

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