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Changing standard form to slope intercept form.

  1. Apr 20, 2016 #1
    1. The problem statement, all variables and given/known data
    Write the equation 4x – 7y – 14 = 0 in the form y = mx + b.

    2. Relevant equations
    "Y= mx + b" and "standard form".

    3. The attempt at a solution


    4x – 7y – 14 = 0 (add 14 to both sides of the equation)

    4x – 7y = 14 (subtract 4x from both sides of the equation)

    -7y = -4x + 14 (divide both sides of the equation by -7)

    y = -4x/-7 + 14/-7

    y = 4/7x + (-2)

    so the slope (m) is 4/7 and the initial value (b) is -2


    Is this the correct way to answer this question. thanks for your time to help me :)
     
  2. jcsd
  3. Apr 20, 2016 #2

    Math_QED

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    Correct, well done
     
  4. Apr 20, 2016 #3
    Thank you alot. Now I know I'm doing it the correct way :)
     
  5. Apr 20, 2016 #4

    SammyS

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    We usually refer to b as the y-intercept rather than the initial value.
     
  6. Apr 20, 2016 #5

    epenguin

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    At the start you could have saved at least one operation by adding 7y to both sides.
     
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