Write f(x) = |x2-x-12| as a piecewise function.
The Attempt at a Solution
-x2+x+12 where x>1/2
x2-x-12 where x[itex]\geq[/itex]0
According to the answer book the answers are
-x2+x+12 where -3<x<4
x2-x-12 where x[itex]\geq[/itex]4
I am really bad at functions when it comes to domain and range..